[FORUM DOLLARS] Math questions!
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*Legendoflegaia.net is not responsible for any transactions that may go wrong UNLESS they're done in forum dollars and you can prove that the transaction has gone wrong. By having a service done with real money, you're on your own.
*If you're scammed in any way, name the scammer with proof of what they did in the scammer thread.
*Read the scammer thread before accepting or giving services from or to someone.
*If the good or service you're offering/requesting is in forum dollars, put [FORUM DOLLARS] in the topic title.
*If the good or service you're offering/requesting is in cash, put [CASH] in the topic title.
*If it's a service you're offering/requesting, please put in the topic title whether it's a request or offer.
*If the topic is regarding a "good" then put "need" or "selling" in the topic title.
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Redhollowlives999
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Re: [FORUM DOLLARS] Math questions!
All that for 25G? Iunno man. Maybe 250? (Assuming you're modifying their money instead of donating).
Then again I don't math anymore and I have +10,000 gold now so I can't really complain.
Then again I don't math anymore and I have +10,000 gold now so I can't really complain.
it really do be like that tho
Re: [FORUM DOLLARS] Math questions!
It's my own G lol.
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Redhollowlives999
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Re: [FORUM DOLLARS] Math questions!
Well then.
DONATION POOL FOR THE MATH THREAD!
DONATION POOL FOR THE MATH THREAD!
it really do be like that tho
Re: [FORUM DOLLARS] Math questions!
Ok, so the encryption was to take a letter from the ASCII table of 128 characters using their decimal digit.
A-B = 65-90
a-b = 97-122
! = 33
You take these letters decimal number and then use the formula I gave you to change their number:
(x^2 + 4)mod 127
So this creates the following "encryption" of letters:
A=38 , a=15
B=42 , b=83
C=48 , c=26
D=56 , d=98
E=66 , e=45
F=78 , f=121
G=92 , g=72
H=108 , h=25
I=126 , i=107
J=19 , j=64
K=41 , k=23
L=65 , l=111
M=91 , m=74
N=119 , n=39
O=22 , o=6
P=54 , p=102
Q=88 , q=73
R=124 , r=46
S=35 , s=21
T=75 , t=125
U=117 , u=104
V=34 , v=85
W=80 , w=68
X=1 , x=53
Y=51 , y=40
Z=103 , z=29
!=77
Now, if you convert these decimals to hex (I'll let you do that), you can see that the message says:
A-B = 65-90
a-b = 97-122
! = 33
You take these letters decimal number and then use the formula I gave you to change their number:
(x^2 + 4)mod 127
So this creates the following "encryption" of letters:
A=38 , a=15
B=42 , b=83
C=48 , c=26
D=56 , d=98
E=66 , e=45
F=78 , f=121
G=92 , g=72
H=108 , h=25
I=126 , i=107
J=19 , j=64
K=41 , k=23
L=65 , l=111
M=91 , m=74
N=119 , n=39
O=22 , o=6
P=54 , p=102
Q=88 , q=73
R=124 , r=46
S=35 , s=21
T=75 , t=125
U=117 , u=104
V=34 , v=85
W=80 , w=68
X=1 , x=53
Y=51 , y=40
Z=103 , z=29
!=77
Now, if you convert these decimals to hex (I'll let you do that), you can see that the message says:
Now, the question is how to decrypt this.... I didn't create the document on how I decrypted this and I somehow forgot, so I'll get back to you on that (or you can solve it) lol.Legend of Legaia is so cool!
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Re: [FORUM DOLLARS] Math questions!
Reward: 20G
Just a simple counting question. I know Night said he could get this really easy, so I'd like to challenge those who don't think they can get it. If no one gets it within a week, go ahead and answer it Night.
Question: 251 tickets are given to 251 different people in an audience. There are five different prizes to be given to some lucky winners of the right numbers. How many ways can the prizes be awarded to the people in the audience if the people holding ticket number 241, 200, and 39 all win prizes, but the people holding ticket numbers 112 and 84 do not win any prizes?
Give the full integer number and explain how you got the integer value.
Just a simple counting question. I know Night said he could get this really easy, so I'd like to challenge those who don't think they can get it. If no one gets it within a week, go ahead and answer it Night.
Question: 251 tickets are given to 251 different people in an audience. There are five different prizes to be given to some lucky winners of the right numbers. How many ways can the prizes be awarded to the people in the audience if the people holding ticket number 241, 200, and 39 all win prizes, but the people holding ticket numbers 112 and 84 do not win any prizes?
Give the full integer number and explain how you got the integer value.
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Re: [FORUM DOLLARS] Math questions!
There are 251 people. 3 people are guaranteed. Leaving 248. 2 more people are guaranteed not to win. Leaving 246 possibilities.
There are 246 possibilities for the first winner, and 245 for the next winner (subtracting the ticket from the first winner).
245*246 = 60270
I haven't taken discrete mathematics in a long time, so I don't know if my reasoning is sound.
There are 246 possibilities for the first winner, and 245 for the next winner (subtracting the ticket from the first winner).
245*246 = 60270
I haven't taken discrete mathematics in a long time, so I don't know if my reasoning is sound.
Re: [FORUM DOLLARS] Math questions!
You're on the right track, but there's a little more to it. Note the prizes are different (I just edited the post in regards to this).
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Redhollowlives999
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Re: [FORUM DOLLARS] Math questions!
I'll take a shot (might as well).
Iunno how the prizes being different correlates much (cuz I'm dumb), but if the prizes being different is the main key here, then would the answer(S) (cuz I'm assuming you're looking for more than one answer here) be:
Prize 4 = 246 different ways (cuz you had to do what U-Nam did but multiply 245 by 1 cuz 1 prize)
and
Prize 5 = 245 different ways (cuz same reason)?
Iunno how the prizes being different correlates much (cuz I'm dumb), but if the prizes being different is the main key here, then would the answer(S) (cuz I'm assuming you're looking for more than one answer here) be:
Prize 4 = 246 different ways (cuz you had to do what U-Nam did but multiply 245 by 1 cuz 1 prize)
and
Prize 5 = 245 different ways (cuz same reason)?
it really do be like that tho
Re: [FORUM DOLLARS] Math questions!
Nope. There's one answer. We're looking at how many possibilities total there are for distributing these prizes to the specified information given.
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Nightshade
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Re: [FORUM DOLLARS] Math questions!
I think I'm going to go ahead and claim victory on this one now.
Do not question yourself with the why or the how. I simply am, and that is all you need to know.